a.√3
b.14⁵/⁹√3
c.4⅓+4⁴/⁹√3
d. 81√3
bantuin jawab kak
Penjelasan dengan langkah-langkah:
cara pengerjaan terlampir
[tex]( \sqrt{3} ) {}^{ - 3} + ( \sqrt{3} {}^{ - 2} + ( \sqrt{3} ) {}^{ - 1 } + ( \sqrt{3}) {}^{0} + ( \sqrt{3} ) {}^{1} + ( \sqrt{3} ) {}^{2} + ( \sqrt{3} ) {}^{3} \\ = \frac{1}{ \sqrt{3 {}^{2} } } + \frac{1}{ \sqrt{3 {}^{3} } } + \frac{1}{ \sqrt{3} } + 1 + \sqrt{3} + 3 + 27 \\ = \frac{1}{27} + \frac{1}{9} + \frac{1}{3} + 1 + \sqrt{3} + 3 + \sqrt[3]{3} \\ = ( \frac{1 + 3 + 9 + 27}{27} )4 \: \sqrt[]{3 + 3} \\ = ( \frac{40}{27} )4 + 4 \sqrt{3 + 3 \\ \frac{}{} } \\ = 1 \frac{13}{27} + 4 + \sqrt[]{3 + 3} \\ = 4 \frac{1}{3} + 4 + \frac{4}{9} \sqrt{3} \\ jawabannya \: C[/tex]
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